|
|
|
Tuesday, 16 february 2010 |
|
|
|
O tabla de sah mai... maricica... |
Proposed by
ily96 |
|
| (5 comments) | 5.887 times displayed |
 |
Pe o tabla de sah 2009*2009 sunt asezati 20092 pioni, cate unul in fiecare casuta.
Fiecare pion se muta intr-o casuta, care are o latura comuna cu casuta lui.
Sa se arate ca ramane o casuta libera. |
|
|
2009=impar. Rezulta 2009*2009=impar => numarul de casute albe nu este egal cu nr de casute negre si presupunem nr casute albe>nr casute negre. Este evident ca pionii de pe casute albe se vor muta in casute negre si invers. Cum nr casute albe> nr casute negre pionii de pe casute albe se vor muta pe un nr mai mic de casute negre=> cel putin doi pioni vor fi in aceeasi casuta => o casuta va fi libera. |
|
|
Tags:
|
O,
tabla,
de,
sah,
mai...,
maricica...
|
|
|
| Similar problems: |
|
sah,
Sah,
chess,
mate in two,
Sah , again,
Sah - Mat-uri simple,...,
can white avoid to loose...,
Sah (alte mat-uri...,
Sah Mat intr-o ......,
Can white win the match?,
Cate patrate...,
Sah...,
Sah,
Sah,
The Chess Game,
Cutting a chess table in...,
Cutting a chess table in...,
Waterloo,
Sah... la rege!,
Tabla inmultirii...
|
|
|
|
|
|
|
 |
Search problems by keywords
|
|
|
|
|
|
|
|
|
|
|
|
Today's Problem
Top 10 most viewed problems