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(4 comments) | 6.871 times displayed |
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Care este al 2011-lea termen in sirul: 1,2,4,7,11,16,....? |
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t1=1
t2=t1+1
t3=t2+2
.....
.....
t2011=t2010+2010
Adunand relatiile obtinem:
t1+t2+....t2010+t2011=t1+t2+....+t2010+1+1+2+....+2010 ,de unde prin reducere avem: t2011=1+2010*2011/2=1+1005*2011. |