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Friday
, 17 september 2010
Proposed by
ixirimdi
(13 comments)
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sol apar pe parcursul zilei
dacä n-or fi aparut deja :)
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Comments (13)
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Friday
, 17 sep 2010 00:16
[#]
pustiul
4+4-4-4=0
4*4/4/4=1
4/4+4/4=2
(4+4+4)/4=3
Friday
, 17 sep 2010 00:17
[#]
pustiul
4+4+4-4=8
Friday
, 17 sep 2010 00:23
[#]
pustiul
4-(4/4)+4=7
Friday
, 17 sep 2010 00:25
[#]
pustiul
(4+4*4)/4=5
Friday
, 17 sep 2010 00:25
[#]
Andrei023
4+4-4-4=0
4/4 + 4-4=1
4/4 + 4/4=2
(4*4 - 4)/4=3
(4-4)/4 + 4=4
(4*4 + 4)/4=5
(4+4)/4 + 4=6
4+4 - 4/4 = 44/4 - 4 = 7
4*4 - 4-4=8
4+4+ 4/4=9
Friday
, 17 sep 2010 01:13
[#]
radufly
0 = 4+4-4-4 = (4-4)*4+4
1 = (4/4)*(4/4) = (4*4)/(4*4) = (4+4)/(4+4) = (4/4)/(4/4)
2 = (4/4)+(4/4) = (4*4)/(4+4) = 4/((4+4)/4)
3 = (4+4+4)/4 = (4*4-4)/4
4 = (4-4)*4+4
5 = (4*4+4)/4
6 = 4+((4+4)/4)
7 = (4+4)-4/4
8 = 4+4+4-4 = (4/4)*4+4 = ((4+4)/4)*4 = 4*4-4-4
9 = 4+4+4/4
Friday
, 17 sep 2010 21:38
[#]
irish_boy23
RE:
0 = (4-4)*4+4 s-au schimbat legile matematicii cumva? "pe vremea mea" orice numar inmultit cu 0 dadea tot 0...dar sper totusi ca ai gresit si ca vei remedia problema..
Friday
, 17 sep 2010 22:16
[#]
radufly
RE:
Da, si in vremurile astea e la fel, dar, scuzele mele, greseala nu e la inmultite, ci am uitat sa pun parantezele la 4+4, deci 0=(4-4)*(4+4) si mai poate fi adaugat si 0=(4-4)*4*4=(4-4)/(4+4)=(4-4)/4*4 s.a.
Friday
, 17 sep 2010 01:25
[#]
radufly
BONUS: daca se adauga si operatiile ca radical, putere, factorial sunt cai de a continua asa pana la 38.
De ex:
32 = 4*4+4*4 = SQRT(4)^(4+4/4) = 4^4/(4/SQRT(4)) = 4*4*4/SQRT(4) = (4+SQRT(4))^SQRT(4)-4
sau
38 = 4! + (4 * 4) - SQRT(4)
Nu s-a reusit inca formarea in acest mod a lui 39 de catre nimeni. Daca cineva reuseste, sa ma anunte si pe mine... sau poate cineva reuseste sa demonstreze ca nu se poate forma pe aceasta cale...
Friday
, 17 sep 2010 17:08
[#]
ixirimdi
RE:
Arata-ne o cale pt a-l obtine pe 35, 36 , 37
si vei obtine o reprezentare pentru 39 :)
Friday
, 17 sep 2010 17:50
[#]
radufly
RE:
Uite:
35 = 4! + (4! - SQRT(4)) / SQRT(4)
36 = 4! + 4 + 4 + 4
37 = 4! + (4! + SQRT(4)) / SQRT(4)
Friday
, 17 sep 2010 23:56
[#]
Andrei023
RE:
Se poate, dar folosind si alte functii.
39 = 4! + 4*4 - (4')!
Friday
, 17 sep 2010 23:11
[#]
ixirimdi
39 = 4! + (4 * 4) - [ SQRT( SQRT(4) ) ]
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