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Wednesday, 10 august 2016 |
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30 de mere la 3 copii |
Proposed by
Gabi |
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| (2 comments) | 1.908 times displayed |
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La o ora de matematica, un elev pune intrebarea daca se pot imparti 30 de mere la 3 copii, in asa fel incat fiecare copil sa primeasca un numar impar de mere (intregi, evident!).
Sa fie oare posibil? Justificati! |
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Un numar impar se scrie sub forma 2 · n + 1. In cazul nostru, cele trei numere impare s-ar scrie sub forma de mai sus, in asa fel incat am avea:
30 = (2 · n1 + 1) + (2 · n2 + 1) + (2 · n3 + 1). Asta ar insemna ca 27 = 2 · (n1 + n2 + n3), fara solutie in multimea numerelor naturale. Deci nu, nu este posibil.
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Tags:
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problema zilei,
probleme de matematica,
amuzante,
matematica amuzanta,
aritmetica,
mere,
copii,
impartire
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